Example

Example: Determining if the Equation x+y2=3x + y^2 = 3 Defines a Function

Consider the equation x+y2=3x + y^2 = 3 where xx is the independent variable. First, isolate the yy term by subtracting xx from both sides to get y2=βˆ’x+3y^2 = -x + 3. Substitute a value for xx, such as x=2x = 2, which yields y2=βˆ’2+3y^2 = -2 + 3, simplifying to y2=1y^2 = 1. This implies that yy can be 11 or βˆ’1-1. Because a single value of xx corresponds to more than one value of yy, the equation x+y2=3x + y^2 = 3 does not define a function.

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Updated 2026-05-06

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