Example

Example: Determining if the Equation x+y2=1x + y^2 = 1 Defines a Function

Consider the equation x+y2=1x + y^2 = 1 with xx as the independent variable. Isolating the yy term by subtracting xx yields y2=x+1y^2 = -x + 1. If a value such as x=0x = 0 is substituted, the equation becomes y2=1y^2 = 1. This results in two possible solutions for yy: 11 and 1-1. Because substituting a single value for xx produces more than one corresponding value for yy, the equation x+y2=1x + y^2 = 1 does not define a function.

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Updated 2026-05-06

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