Example

Example: Evaluating the Function f(x)=2x2+3x1f(x) = 2x^2 + 3x - 1

To evaluate the quadratic function f(x)=2x2+3x1f(x) = 2x^2 + 3x - 1 for a specific value or variable, substitute that value for xx in the expression and simplify using the order of operations:

  • Evaluate f(3)f(3): Replace xx with 33 to get f(3)=2(3)2+3(3)1f(3) = 2(3)^2 + 3(3) - 1. Simplify the exponent to get 2(9)+3(3)12(9) + 3(3) - 1. Multiply to obtain 18+9118 + 9 - 1. Combine the terms to find f(3)=26f(3) = 26.
  • Evaluate f(2)f(-2): Replace xx with 2-2 using parentheses to preserve the negative signs: f(2)=2(2)2+3(2)1f(-2) = 2(-2)^2 + 3(-2) - 1. Simplifying the exponent gives 2(4)612(4) - 6 - 1. Multiply to obtain 8618 - 6 - 1. Simplify to find f(2)=1f(-2) = 1.
  • Evaluate f(a)f(a): Replace xx with the variable aa: f(a)=2(a)2+3(a)1f(a) = 2(a)^2 + 3(a) - 1. Simplify to yield f(a)=2a2+3a1f(a) = 2a^2 + 3a - 1. The same substitution procedure applies when evaluating a function with a variable rather than a constant.

0

1

Updated 2026-05-06

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.3 Graphs and Functions - Intermediate Algebra @ OpenStax

Algebra