Example

Example: Evaluating the Function f(x)=3x22x+1f(x) = 3x^2 - 2x + 1

To evaluate the quadratic function f(x)=3x22x+1f(x) = 3x^2 - 2x + 1 for a specific value or variable, substitute that value for xx in the expression and simplify using the order of operations: - Evaluate f(3)f(3): Replace xx with 33 to get f(3)=3(3)22(3)+1f(3) = 3(3)^2 - 2(3) + 1. Simplify the exponent to get 3(9)2(3)+13(9) - 2(3) + 1. Multiply to obtain 276+127 - 6 + 1. Combine the terms to find f(3)=22f(3) = 22. - Evaluate f(1)f(-1): Replace xx with 1-1 using parentheses to preserve the negative signs: f(1)=3(1)22(1)+1f(-1) = 3(-1)^2 - 2(-1) + 1. Simplifying the exponent gives 3(1)(2)+13(1) - (-2) + 1. Multiply to obtain 3+2+13 + 2 + 1. Simplify to find f(1)=6f(-1) = 6. - Evaluate f(t)f(t): Replace xx with the variable tt: f(t)=3(t)22(t)+1f(t) = 3(t)^2 - 2(t) + 1. Simplify to yield f(t)=3t22t+1f(t) = 3t^2 - 2t + 1. This illustrates that evaluating a function with a variable produces an algebraic expression rather than a numerical value.

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Updated 2026-05-06

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