Example

Example: Graphing 4y216x2=644y^2 - 16x^2 = 64

To graph the equation 4y216x2=644y^2 - 16x^2 = 64, first convert it to standard form by dividing every term by 64: 4y26416x264=6464\frac{4y^2}{64} - \frac{16x^2}{64} = \frac{64}{64}, which simplifies to y216x24=1\frac{y^2}{16} - \frac{x^2}{4} = 1. Since the y2y^2-term is positive, the transverse axis is vertical. From a2=16a^2 = 16, we get a=±4a = \pm 4, so the vertices are (0,4)(0, -4) and (0,4)(0, 4). From b2=4b^2 = 4, we get b=±2b = \pm 2. Sketch the central rectangle intersecting the xx-axis at (2,0)(-2, 0) and (2,0)(2, 0) and the yy-axis at the vertices. Sketch the asymptotes through the diagonals of the rectangle. Finally, draw the two branches of the hyperbola through the vertices, opening upward and downward.

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Updated 2026-05-25

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