Example

Example: Solving an Absolute Value Inequality for Tolerance

Consider a manufacturing scenario where the ideal diameter of a rod for a machine is 6060 mm, and the actual diameter can vary by a manufacturing tolerance of 0.0750.075 mm. To find the acceptable range of diameters, let xx be the actual measurement. Using the absolute value inequality model for tolerance (extactualextidealexttolerance| ext{actual} - ext{ideal}| \leq ext{tolerance}), we can write the inequality: x600.075|x - 60| \leq 0.075 Rewrite this absolute value expression as a compound inequality: 0.075x600.075-0.075 \leq x - 60 \leq 0.075 Solve for xx by adding 6060 to all parts of the inequality: 59.925x60.07559.925 \leq x \leq 60.075 Thus, any rod with a diameter between 59.92559.925 mm and 60.07560.075 mm will be correctly accepted by the customer without causing rejection.

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Updated 2026-04-23

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