Example

Try It: Applying Absolute Value Inequalities to Tolerance

Practicing with manufacturing tolerances helps reinforce the algebraic procedure for solving absolute value inequalities. In these applications, the formula actualidealtolerance|\text{actual} - \text{ideal}| \leq \text{tolerance} is consistently used. For instance, if an ideal rod diameter is 8080 mm with an allowed actual variation of 0.0090.009 mm, we set up the absolute value inequality x800.009|x - 80| \leq 0.009. Translating this to 0.009x800.009-0.009 \leq x - 80 \leq 0.009 and solving yields an acceptable diameter range tightly positioned between 79.99179.991 mm and 80.00980.009 mm. Similarly, if the ideal machine part diameter is 7575 mm and the tolerance is slightly larger at 0.050.05 mm, the resulting inequality x750.05|x - 75| \leq 0.05 is solved to completely identify the valid acceptable range squarely spanning from 74.9574.95 mm to 75.0575.05 mm.

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Updated 2026-04-23

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