Example

Factoring 100h2100 - h^2

Factor 100h2100 - h^2 by recognizing it as a difference of squares even though the constant term appears first — a "backwards" arrangement.

Step 1 — Is this a difference of squares? Yes. The expression is still a difference of two perfect squares, just written with the constant before the variable:

  • 100=(10)2100 = (10)^2, so a=10a = 10.
  • h2=(h)2h^2 = (h)^2, so b=hb = h.

Rewrite to show the squared structure: (10)2(h)2(10)^2 - (h)^2.

Step 2 — Factor as the product of conjugates. Apply the difference of squares pattern with a=10a = 10 and b=hb = h:

100h2=(10h)(10+h)100 - h^2 = (10 - h)(10 + h)

Step 3 — Check by multiplying: (10h)(10+h)=100+10h10hh2=100h2(10 - h)(10 + h) = 100 + 10h - 10h - h^2 = 100 - h^2

The factored form is (10h)(10+h)(10 - h)(10 + h).

Important caution: Do not rearrange the original expression to h2100h^2 - 100 before factoring. Factoring h2100h^2 - 100 gives (h10)(h+10)(h - 10)(h + 10), which is a different — though related — result. The order of the original terms determines the order of the terms in the conjugate factors. To see the difference, compare: factoring 100h2100 - h^2 yields (10h)(10+h)(10 - h)(10 + h), while factoring h2100h^2 - 100 yields (h10)(h+10)(h - 10)(h + 10).

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Updated 2026-04-21

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