Example

Factoring 64y2164y^2 - 1

To factor 64y2164y^2 - 1, recognize it as a difference of squares: (8y)212(8y)^2 - 1^2. Applying the pattern a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b) with a=8ya = 8y and b=1b = 1 results in the product of conjugates (8y1)(8y+1)(8y - 1)(8y + 1). Checking by multiplying confirms (8y1)(8y+1)=64y21(8y - 1)(8y + 1) = 64y^2 - 1.

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Updated 2026-04-30

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