Finding Walking and Biking Speeds Using Equal Distances
Apply the distance, rate, and time problem-solving strategy to find two unknown speeds when both trips cover the same distance but use different modes of travel, requiring a unit conversion from minutes to hours and clearing fractions to solve.
Problem: When Naoko walks to school, it takes her minutes. If she rides her bike, it takes her minutes. Her biking speed is miles per hour faster than her walking speed. What are her walking speed and her biking speed?
- Read and draw: Sketch the route from home to school. The walking path ( minutes) and the biking path ( minutes, mph faster) cover the same distance. Create a rate–time–distance table.
- Identify: The walking speed and the biking speed.
- Name: Let = walking speed in mph. Then the biking speed is . Because the rate is in miles per hour, convert the times into hours: minutes is or hour, and minutes is or hour. Multiply rate by time to fill in the distance column:
| Rate (mph) | Time (hrs) | Distance (miles) | |
|---|---|---|---|
| Walk | |||
| Bike |
- Translate: The distance from home to school is the same whether Naoko walks or bikes:
- Solve: Clear the fractions by multiplying both sides by the LCD of and , which is :
Subtract from both sides: . The walking speed is mph. Her biking speed is mph.
-
Check: Walk: miles. Bike: miles. Both distances are miles.
-
Answer: Naoko's walking speed is mph and her biking speed is mph.
This example extends the equal-distance uniform motion scenario by requiring a time conversion before setup and solving an algebraic equation with fractional coefficients.
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