Example

Graphing y=2x24x3y = 2x^2 - 4x - 3

To graph the parabola y=2x24x3y = 2x^2 - 4x - 3, apply the systematic graphing procedure:

Step 1: The equation is already written with yy on one side.

Step 2: The coefficient a=2a = 2 is positive, so the parabola opens upward.

Step 3: Find the axis of symmetry using x=b2ax = -\frac{b}{2a}. Since b=4b = -4 and a=2a = 2, x=42(2)=44=1x = -\frac{-4}{2(2)} = -\frac{-4}{4} = 1. The axis of symmetry is the line x=1x = 1.

Step 4: Find the vertex by substituting x=1x = 1 into the equation: y=2(1)24(1)3=2(1)43=243=5y = 2(1)^2 - 4(1) - 3 = 2(1) - 4 - 3 = 2 - 4 - 3 = -5. The vertex is the point (1,5)(1, -5).

Step 5: Find the yy-intercept by setting x=0x = 0: y=2(0)24(0)3=3y = 2(0)^2 - 4(0) - 3 = -3. The yy-intercept is (0,3)(0, -3). The point symmetric to the yy-intercept across the axis of symmetry x=1x = 1 is (2,3)(2, -3).

Step 6: Find the xx-intercepts by setting y=0y = 0: 0=2x24x30 = 2x^2 - 4x - 3. This quadratic does not factor, so use the Quadratic Formula with a=2a = 2, b=4b = -4, and c=3c = -3:

x=(4)±(4)24(2)(3)2(2)x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-3)}}{2(2)}

Simplify under the radical:

x=4±16+244x = \frac{4 \pm \sqrt{16 + 24}}{4} x=4±404x = \frac{4 \pm \sqrt{40}}{4}

Simplify the radical (40=210\sqrt{40} = 2\sqrt{10}):

x=4±2104x = \frac{4 \pm 2\sqrt{10}}{4}

Factor out 22 from the numerator to reduce the fraction:

x=2(2±10)4=2±102x = \frac{2(2 \pm \sqrt{10})}{4} = \frac{2 \pm \sqrt{10}}{2}

The approximate values of the xx-intercepts are (2.5,0)(2.5, 0) and (0.6,0)(-0.6, 0).

Step 7: Graph the parabola by plotting the vertex, the yy-intercept, the symmetric point, and the xx-intercepts, then connecting these points with a smooth, upward-opening curve.

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Updated 2026-04-21

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