Example

Graphing y=3x26x+5y = -3x^2 - 6x + 5

To graph the parabola y=3x26x+5y = -3x^2 - 6x + 5, apply the systematic graphing procedure:

Step 1: The coefficient a=3a = -3 is negative, so the parabola opens downward.

Step 2: Find the axis of symmetry using x=b2ax = -\frac{b}{2a}. Since a=3a = -3 and b=6b = -6, x=62(3)=66=1x = -\frac{-6}{2(-3)} = -\frac{-6}{-6} = -1. The axis of symmetry is the line x=1x = -1.

Step 3: Find the vertex by substituting x=1x = -1 into the equation: y=3(1)26(1)+5=3(1)+6+5=3+6+5=8y = -3(-1)^2 - 6(-1) + 5 = -3(1) + 6 + 5 = -3 + 6 + 5 = 8. The vertex is the point (1,8)(-1, 8).

Step 4: Find the yy-intercept by setting x=0x = 0: y=3(0)26(0)+5=5y = -3(0)^2 - 6(0) + 5 = 5. The yy-intercept is (0,5)(0, 5). The point symmetric to the yy-intercept across the axis of symmetry x=1x = -1 is (2,5)(-2, 5).

Step 5: Find the xx-intercepts by setting y=0y = 0: 0=3x26x+50 = -3x^2 - 6x + 5. Use the Quadratic Formula with a=3a = -3, b=6b = -6, and c=5c = 5:

x=(6)±(6)24(3)(5)2(3)x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(-3)(5)}}{2(-3)} x=6±36+606x = \frac{6 \pm \sqrt{36 + 60}}{-6} x=6±966x = \frac{6 \pm \sqrt{96}}{-6} x=6±466x = \frac{6 \pm 4\sqrt{6}}{-6}

Factor out 22 from the numerator and denominator to simplify:

x=2(3±26)6=3±263x = \frac{2(3 \pm 2\sqrt{6})}{-6} = \frac{3 \pm 2\sqrt{6}}{-3}

The approximate values of the xx-intercepts are (2.6,0)(-2.6, 0) and (0.6,0)(0.6, 0).

Step 6: Graph the parabola by plotting the vertex, the yy-intercept, the symmetric point, and the xx-intercepts, then connecting them with a smooth, downward-opening curve.

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Updated 2026-04-21

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