Example

Graphing y=−3x2−6x+5y = -3x^2 - 6x + 5

To graph the parabola y=−3x2−6x+5y = -3x^2 - 6x + 5, apply the systematic graphing procedure:

Step 1: The coefficient a=−3a = -3 is negative, so the parabola opens downward.

Step 2: Find the axis of symmetry using x=−b2ax = -\frac{b}{2a}. Since a=−3a = -3 and b=−6b = -6, x=−−62(−3)=−−6−6=−1x = -\frac{-6}{2(-3)} = -\frac{-6}{-6} = -1. The axis of symmetry is the line x=−1x = -1.

Step 3: Find the vertex by substituting x=−1x = -1 into the equation: y=−3(−1)2−6(−1)+5=−3(1)+6+5=−3+6+5=8y = -3(-1)^2 - 6(-1) + 5 = -3(1) + 6 + 5 = -3 + 6 + 5 = 8. The vertex is the point (−1,8)(-1, 8).

Step 4: Find the yy-intercept by setting x=0x = 0: y=−3(0)2−6(0)+5=5y = -3(0)^2 - 6(0) + 5 = 5. The yy-intercept is (0, 5). The point symmetric to the yy-intercept across the axis of symmetry x=−1x = -1 is (−2,5)(-2, 5).

Step 5: Find the xx-intercepts by setting y=0y = 0: 0=−3x2−6x+50 = -3x^2 - 6x + 5. Use the Quadratic Formula with a=−3a = -3, b=−6b = -6, and c=5c = 5:

x=−(−6)±(−6)2−4(−3)(5)2(−3)x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(-3)(5)}}{2(-3)} x=6±36+60−6x = \frac{6 \pm \sqrt{36 + 60}}{-6} x=6±96−6x = \frac{6 \pm \sqrt{96}}{-6} x=6±46−6x = \frac{6 \pm 4\sqrt{6}}{-6}

Factor out 22 from the numerator and denominator to simplify:

x=2(3±26)−6=3±26−3x = \frac{2(3 \pm 2\sqrt{6})}{-6} = \frac{3 \pm 2\sqrt{6}}{-3}

The approximate values of the xx-intercepts are (−2.6,0)(-2.6, 0) and (0.6, 0).

Step 6: Graph the parabola by plotting the vertex, the yy-intercept, the symmetric point, and the xx-intercepts, then connecting them with a smooth, downward-opening curve.

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Updated 2026-04-21

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