Example

Multiplying (b3)(b+6)(b - 3)(b + 6) Using the FOIL Method

Multiply (b3)(b+6)(b - 3)(b + 6) using the FOIL method.

Step 1 — First: Multiply the first terms: bb=b2b \cdot b = b^2.

Step 2 — Outer: Multiply the outermost terms: b6=6bb \cdot 6 = 6b.

Step 3 — Inner: Multiply the innermost terms: (3)b=3b(-3) \cdot b = -3b.

Step 4 — Last: Multiply the last terms: (3)6=18(-3) \cdot 6 = -18.

Writing all four products in order gives: b2+6b3b18b^2 + 6b - 3b - 18

Step 5 — Combine like terms: The Outer and Inner products 6b6b and 3b-3b are like terms: 6b+(3b)=3b6b + (-3b) = 3b.

The simplified result is b2+3b18b^2 + 3b - 18.

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Updated 2026-04-29

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