Example

Simplifying (1+3x)2(1 + 3\sqrt{x})^2

Apply the Binomial Squares Pattern to square a binomial that includes a variable inside a square root.

Use the addition form (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2, where a=1a = 1 and b=3xb = 3\sqrt{x}.

Step 1 — Square the first term: 12=11^2 = 1.

Step 2 — Double the product of the two terms: 213x=6x2 \cdot 1 \cdot 3\sqrt{x} = 6\sqrt{x}.

Step 3 — Square the last term: (3x)2=9x(3\sqrt{x})^2 = 9x. Square the coefficient and the radical separately: 32=93^2 = 9 and (x)2=x(\sqrt{x})^2 = x.

Assemble the three pieces:

(1+3x)2=1+6x+9x(1 + 3\sqrt{x})^2 = 1 + 6\sqrt{x} + 9x

No like terms remain to combine, so the result stays as a three-term expression. This example extends the Binomial Squares Pattern to a binomial whose second term is a coefficient times a variable square root. The critical observation is that (3x)2=9x(3\sqrt{x})^2 = 9x, not 3x3x — both the numerical coefficient and the radical must be squared independently.

0

1

Updated 2026-04-21

Contributors are:

Who are from:

Tags

OpenStax

Elementary Algebra @ OpenStax

Ch.9 Roots and Radicals - Elementary Algebra @ OpenStax

Algebra

Math

Prealgebra

Related
Learn After