Example

Squaring (2x3y)2(2x - 3y)^2 Using the Binomial Squares Pattern

Apply the Binomial Squares Pattern to multiply (2x3y)2(2x - 3y)^2. Because the binomial involves subtraction, use the form (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2, where a=2xa = 2x and b=3yb = 3y.

Step 1 — Square the first term: (2x)2=4x2(2x)^2 = 4x^2. Both the coefficient and the variable are squared: 22=42^2 = 4 and x2=x2x^2 = x^2.

Step 2 — Square the last term: (3y)2=9y2(3y)^2 = 9y^2. Again, square both parts: 32=93^2 = 9 and y2=y2y^2 = y^2.

Step 3 — Double their product: 2(2x)(3y)=12xy2 \cdot (2x) \cdot (3y) = 12xy. Because the binomial uses subtraction, the middle term is negative: 12xy-12xy.

Assemble the three pieces into a trinomial:

(2x3y)2=4x212xy+9y2(2x - 3y)^2 = 4x^2 - 12xy + 9y^2

This example extends the pattern to a binomial whose two terms contain different variables (xx and yy), each with a numerical coefficient greater than 11. When squaring the first and last terms, both the coefficient and the variable must be squared separately — for instance, (2x)2=22x2=4x2(2x)^2 = 2^2 \cdot x^2 = 4x^2, not 2x22x^2. The middle term 12xy12xy involves the product of both variables, producing a two-variable trinomial.

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Updated 2026-04-21

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