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Solving a Direct Variation Application: Calories Burned Exercising

Apply the problem-solving strategy for direct variation to determine calories burned during exercise. If the number of calories burned, cc, varies directly with the amount of time spent exercising, tt, the general formula is c=ktc = kt. Given that 312312 calories are burned in 6565 minutes, substitute these values to find the constant: 312=k(65)312 = k(65), which gives k=4.8k = 4.8. The specific equation is c=4.8tc = 4.8t. To find the calories burned in 9090 minutes, substitute t=90t = 90 into the equation: c=4.8(90)c = 4.8(90), resulting in c=432c = 432. Thus, 432432 calories would be burned.

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Updated 2026-05-01

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