Example

Solving 25p2=4925p^2 = 49 by Factoring

Solve the quadratic equation 25p2=4925p^2 = 49 by applying the factoring method.

Step 1 — Write in standard form. Subtract 4949 from both sides: 25p249=025p^2 - 49 = 0

Step 2 — Factor the quadratic expression. The binomial is a difference of squares. (5p7)(5p+7)=0(5p - 7)(5p + 7) = 0

Step 3 — Apply the Zero Product Property. Set each factor equal to zero: 5p7=0or5p+7=05p - 7 = 0 \quad \text{or} \quad 5p + 7 = 0

Step 4 — Solve each linear equation: p=75orp=75p = \frac{7}{5} \quad \text{or} \quad p = -\frac{7}{5}

Step 5 — Check both solutions by substituting into the original equation 25p2=4925p^2 = 49: For p=75p = \frac{7}{5}: 25(75)2=25(4925)=4925\left(\frac{7}{5}\right)^2 = 25\left(\frac{49}{25}\right) = 49 ✓ For p=75p = -\frac{7}{5}: 25(75)2=25(4925)=4925\left(-\frac{7}{5}\right)^2 = 25\left(\frac{49}{25}\right) = 49 ✓ The solutions are p=75p = \frac{7}{5} and p=75p = -\frac{7}{5}.

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Updated 2026-04-30

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