Example

Solving 4z3=3z+2\sqrt{4z-3} = \sqrt{3z+2}

Solve the radical equation 4z3=3z+2\sqrt{4z - 3} = \sqrt{3z + 2}, which has square root expressions on both sides of the equation.

Step 1 — Isolate the radical. Both radical terms are already isolated — each side of the equation consists of a single square root expression, so no rearrangement is needed.

Step 2 — Square both sides. Apply the Squaring Property to each side independently:

(4z3)2=(3z+2)2(\sqrt{4z - 3})^2 = (\sqrt{3z + 2})^2

4z3=3z+24z - 3 = 3z + 2

Step 3 — Solve the new equation. Both radicals have been eliminated, leaving a linear equation. Subtract 3z3z from both sides: z3=2z - 3 = 2. Add 33 to both sides: z=5z = 5.

Step 4 — Check. Substitute z=5z = 5 into the original equation:

4(5)3=3(5)+2\sqrt{4(5) - 3} = \sqrt{3(5) + 2}

17=17\sqrt{17} = \sqrt{17}

Since 17=17\sqrt{17} = \sqrt{17} is true, z=5z = 5 is confirmed as the solution. When a radical equation has square roots on both sides, squaring eliminates both radicals simultaneously — the Squaring Property is applied to each side, and the result is a standard linear equation with no radicals remaining.

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Updated 2026-04-21

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