Example

Solving (x2)2+3=30(x - 2)^2 + 3 = 30 Using the Square Root Property

Solve (x2)2+3=30(x - 2)^2 + 3 = 30 by first isolating the squared binomial and then applying the Square Root Property. Unlike earlier examples where the binomial square was already isolated, this equation has an additional constant term that must be removed before the property can be used.

Isolate the binomial term. Subtract 33 from both sides:

(x2)2=27(x - 2)^2 = 27

Apply the Square Root Property:

x2=±27x - 2 = \pm\sqrt{27}

Simplify the radical. The largest perfect square factor of 2727 is 99. Rewrite 2727 as 939 \cdot 3 and apply the Product Property:

27=93=33\sqrt{27} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}

So x2=±33x - 2 = \pm 3\sqrt{3}.

Solve for xx by adding 22 to both sides:

x=2±33x = 2 \pm 3\sqrt{3}

Rewrite as two solutions:

x=2+33,x=233x = 2 + 3\sqrt{3}, \quad x = 2 - 3\sqrt{3}

This example demonstrates that when a squared-binomial equation has additional terms on the same side as the binomial, those terms must be isolated first — much like Step 1 in the general procedure requires isolating the quadratic term before applying the Square Root Property. The resulting radical 27\sqrt{27} is not in simplified form and must be reduced using the Product Property of Square Roots.

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Updated 2026-04-21

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