Example

Solving 2(x2)2+3=572(x - 2)^2 + 3 = 57 Using the Square Root Property

Solve the equation 2(x2)2+3=572(x - 2)^2 + 3 = 57 using the Square Root Property. First, subtract 33 from both sides to isolate the binomial term, resulting in 2(x2)2=542(x - 2)^2 = 54. Then, divide both sides by 22 to get (x2)2=27(x - 2)^2 = 27. Now apply the Square Root Property to obtain x2=±27x - 2 = \pm\sqrt{27}. Simplify the radical to x2=±33x - 2 = \pm 3\sqrt{3}. Finally, solve for xx by adding 22 to both sides, yielding x=2±33x = 2 \pm 3\sqrt{3}. Rewrite to show the two individual solutions: x=2+33x = 2 + 3\sqrt{3} and x=233x = 2 - 3\sqrt{3}.

0

1

Updated 2026-05-26

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.9 Quadratic Equations and Functions - Intermediate Algebra @ OpenStax

Algebra

Related