Example

Try It 7.103: Solving a Direct Variation Application for Calories Burned

Apply the problem-solving strategy for direct variation to determine calories burned during exercise. If the number of calories, cc, burned varies directly with the amount of time, tt, spent exercising, the general formula is c=ktc = kt. Given that Arnold burned 312312 calories in 6565 minutes, substitute these values to find the constant of variation: 312=k(65)312 = k(65), which gives k=4.8k = 4.8. The specific equation relating cc and tt is c=4.8tc = 4.8t. To find the calories he would burn if he exercises for 9090 minutes, substitute t=90t = 90 into the equation: c=4.8(90)c = 4.8(90), resulting in c=432c = 432. Thus, Arnold would burn 432432 calories.

0

1

Updated 2026-05-25

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.7 Rational Expressions and Functions - Intermediate Algebra @ OpenStax

Algebra

Related
Learn After