Example

Try It 10.48: Solving loga64=3\log_a 64 = 3 and lnx=9\ln x = 9

To solve the logarithmic equations loga64=3\log_a 64 = 3 and lnx=9\ln x = 9, rewrite each expression as an exponential equation. For loga64=3\log_a 64 = 3, the equivalent exponential form is a3=64a^3 = 64. Taking the cube root of both sides gives a=4a = 4. Since this base is positive, it is a valid solution. For the natural logarithmic equation lnx=9\ln x = 9, converting it to exponential form results directly in x=e9x = e^9. This is the exact solution for the variable xx.

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Updated 2026-05-25

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Ch.10 Exponential and Logarithmic Functions - Intermediate Algebra @ OpenStax

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