Example

Try It 10.50: Solving log3(4x+3)=3\log_3(4x + 3) = 3 and lne4x=4\ln e^{4x} = 4

To solve the logarithmic equation log3(4x+3)=3\log_3(4x + 3) = 3, begin by rewriting it in exponential form as 33=4x+33^3 = 4x + 3. Evaluating the exponent gives 27=4x+327 = 4x + 3. Subtracting 33 from both sides results in 24=4x24 = 4x, and dividing by 44 yields the solution x=6x = 6.

To solve the natural logarithmic equation lne4x=4\ln e^{4x} = 4, express it in exponential form as e4=e4xe^4 = e^{4x}. Because the bases are the same, the exponents are equal, which leads to the equation 4=4x4 = 4x. Dividing both sides by 44 provides the solution x=1x = 1.

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Updated 2026-05-25

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Ch.10 Exponential and Logarithmic Functions - Intermediate Algebra @ OpenStax

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