Example

Try It 10.49: Solving log2(5x1)=6\log_2(5x - 1) = 6 and lne3x=6\ln e^{3x} = 6

To solve the logarithmic equation log2(5x1)=6\log_2(5x - 1) = 6, rewrite the equation in its exponential form, 26=5x12^6 = 5x - 1. Evaluating the exponent yields 64=5x164 = 5x - 1. Adding 11 to both sides gives 65=5x65 = 5x, and dividing by 55 results in the solution x=13x = 13.

To solve the natural logarithmic equation lne3x=6\ln e^{3x} = 6, convert it to exponential form to obtain e6=e3xe^6 = e^{3x}. Since the bases are identical, set the exponents equal to each other to get 6=3x6 = 3x. Dividing both sides by 33 yields the solution x=2x = 2.

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Updated 2026-05-25

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Ch.10 Exponential and Logarithmic Functions - Intermediate Algebra @ OpenStax

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