Example

Classifying 12c+5(5+3c)=3(9c4)12c + 5(5 + 3c) = 3(9c - 4)

To classify the equation 12c+5(5+3c)=3(9c4)12c+5(5+3c)=3(9c-4), distribute the coefficients on both sides to produce 12c+25+15c=27c1212c+25+15c=27c-12. Combine the like terms on the left side to obtain 27c+25=27c1227c+25=27c-12. By subtracting 27c27c from both sides, the variables are entirely eliminated, leaving the definitively false numerical assertion 25=1225=-12. Since there is no valid substitution for cc that can satisfy this false statement, the original equation is classified as a contradiction with no solution.

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Updated 2026-05-02

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