Example

Classifying 6(2n−1)+3=2n−8+5(2n+1)6(2n - 1) + 3 = 2n - 8 + 5(2n + 1)

To determine whether 6(2n−1)+3=2n−8+5(2n+1)6(2n - 1) + 3 = 2n - 8 + 5(2n + 1) is a conditional equation, an identity, or a contradiction, simplify both sides. Distributing yields 12n−6+3=2n−8+10n+512n - 6 + 3 = 2n - 8 + 10n + 5. Combining like terms simplifies the given equation down to 12n−3=12n−312n - 3 = 12n - 3. Subtracting 12n12n from each side to isolate the variable removes nn entirely, leaving the true constant statement −3=−3-3 = -3. Because this statement is inherently true independent of the value of nn, the equation is classified as an identity and its solution is all real numbers.

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Updated 2026-06-18

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