Example

Classifying 7y+14=7(y+2)7y + 14 = 7(y + 2)

To determine the classification of the linear equation 7y+14=7(y+2)7y + 14 = 7(y + 2), apply the properties of equality. First, distribute the 77 on the right side to get 7y+14=7y+147y + 14 = 7y + 14. Next, subtract 7y7y from both sides to group the variable terms, which results in 14=1414 = 14. The variables are completely eliminated, leaving a numerical statement that is universally true. Because the equation evaluates to a true statement regardless of the value of yy, the original equation is classified as an identity, meaning its solution set is all real numbers.

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Updated 2026-04-22

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Ch.2 Solving Linear Equations - Intermediate Algebra @ OpenStax

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