Example

Classifying 5m+3(9+3m)=2(7m11)5m + 3(9 + 3m) = 2(7m - 11)

To classify the linear equation 5m+3(9+3m)=2(7m11)5m + 3(9 + 3m) = 2(7m - 11), first distribute on both sides to get 5m+27+9m=14m225m + 27 + 9m = 14m - 22. By combining like terms on the left side, the equation simplifies to 14m+27=14m2214m + 27 = 14m - 22. Subtracting 14m14m from both sides eliminates the variable entirely, resulting in the statement 27=2227 = -22. Because this is a false statement mathematically, the original equation cannot be true for any value of the variable mm. Thus, it is classified as a contradiction and has no solution.

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Updated 2026-04-22

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Ch.2 Solving Linear Equations - Intermediate Algebra @ OpenStax

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