Example

Example: Solving and Graphing 5(3x1)105(3x-1) \leq 10 and 4(x+3)<84(x+3) < 8

To solve the compound inequality 5(3x1)105(3x-1) \leq 10 and 4(x+3)<84(x+3) < 8, begin by solving each inequality independently. Distributing the 55 in the first inequality gives 15x51015x - 5 \leq 10, which simplifies to 15x1515x \leq 15 or x1x \leq 1. Distributing the 44 in the second inequality yields 4x+12<84x + 12 < 8, which simplifies to 4x<44x < -4 or x<1x < -1. Graphing both results on a number line shows that the intersection of x1x \leq 1 and x<1x < -1 is the set of all numbers where x<1x < -1. In interval notation, this overlapping solution is written as (,1)(-\infty, -1).

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Updated 2026-06-25

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