Example

Factoring 250m3+432n3250m^3 + 432n^3

Factor 250m3+432n3250m^3 + 432n^3 completely.

First, check for a greatest common factor. Both terms share a numerical factor of 22. Factor it out: 2(125m3+216n3)2(125m^3 + 216n^3)

Next, the expression inside the parentheses is a binomial. Because 125m3=(5m)3125m^3 = (5m)^3 and 216n3=(6n)3216n^3 = (6n)^3, it is a sum of cubes.

Apply the sum of cubes pattern a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2) with a=5ma = 5m and b=6nb = 6n: 2((5m)3+(6n)3)2((5m)^3 + (6n)^3) 2(5m+6n)((5m)2(5m)(6n)+(6n)2)2(5m + 6n)((5m)^2 - (5m)(6n) + (6n)^2)

Simplify the trinomial factor to obtain the completely factored form: 2(5m+6n)(25m230mn+36n2)2(5m + 6n)(25m^2 - 30mn + 36n^2)

Multiply to check the result.

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Updated 2026-04-30

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