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Factoring
Factor completely by first extracting a GCF that includes a variable, then applying the difference of squares pattern to the remaining binomial.
Step 1 — Is there a GCF? Yes. The two terms and share a numerical factor of and a variable factor of . The GCF is . Factor it out:
Step 2 — Is the binomial a difference of squares? Yes: and , so .
Step 3 — Factor as a product of conjugates. Apply the pattern with and :
Step 4 — Check by multiplying:
✓
The completely factored form is . This example illustrates how a common factor — here , which includes a variable — can disguise a difference of squares. Neither nor appears to be a perfect square on its own; only after extracting the GCF of does the recognizable structure emerge inside the parentheses. Always look for a common factor first, because it may reveal a special product pattern that would otherwise remain hidden.
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Ch.7 Factoring - Elementary Algebra @ OpenStax
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Learn After
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