Example

Factoring 2n28n422n^2 - 8n - 42

Factor 2n28n422n^2 - 8n - 42 completely by first extracting the GCF and then factoring the resulting trinomial.

Step 1 — Check for a GCF: The three terms 2n22n^2, 8n-8n, and 42-42 all share a factor of 22. Factor it out: 2(n24n21)2(n^2 - 4n - 21).

Step 2 — Classify the expression inside the parentheses: The expression n24n21n^2 - 4n - 21 is a trinomial with a leading coefficient of 1, so the "undo FOIL" method applies. Set up two binomials: (n)(n)(n\quad)(n\quad).

Step 3 — Find two numbers whose product is 21-21 and whose sum is 4-4. List the factor pairs of 21-21 and check their sums:

Factors of 21-21Sum of factors
1,211, -211+(21)=201 + (-21) = -20
3,73, -73+(7)=43 + (-7) = -4

The pair 33 and 7-7 works.

Step 4 — Write the fully factored form: 2(n+3)(n7)2(n + 3)(n - 7).

Step 5 — Check by multiplying: 2(n+3)(n7)=2(n27n+3n21)=2(n24n21)=2n28n422(n + 3)(n - 7) = 2(n^2 - 7n + 3n - 21) = 2(n^2 - 4n - 21) = 2n^2 - 8n - 42 ✓.

The completely factored form is 2(n+3)(n7)2(n + 3)(n - 7). This example illustrates a two-step factoring process: extracting the GCF first reduces the leading coefficient to 1, which then allows the simpler "undo FOIL" trinomial factoring method to be applied to the expression inside the parentheses. Always remember to check for a GCF before attempting other factoring techniques.

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Updated 2026-04-21

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