Example

Factoring 5x325x25x^3 - 25x^2

Factor 5x325x25x^3 - 25x^2 by extracting the greatest common factor, which in this case includes a variable component.

Step 1 — Find the GCF of 5x35x^3 and 25x225x^2: Factor each term into primes and expanded variables: 5x3=5xxx5x^3 = 5 \cdot x \cdot x \cdot x and 25x2=55xx25x^2 = 5 \cdot 5 \cdot x \cdot x. The factors common to both are one 55 and two xxs, so GCF=5xx=5x2\text{GCF} = 5 \cdot x \cdot x = 5x^2.

Step 2 — Rewrite each term as a product of the GCF: Express 5x3=5x2x5x^3 = 5x^2 \cdot x and 25x2=5x2525x^2 = 5x^2 \cdot 5, giving 5x2x5x255x^2 \cdot x - 5x^2 \cdot 5.

Step 3 — Factor out the GCF: 5x2(x5)5x^2(x - 5).

Step 4 — Check by multiplying: 5x2(x5)=5x2x5x25=5x325x25x^2(x - 5) = 5x^2 \cdot x - 5x^2 \cdot 5 = 5x^3 - 25x^2 ✓.

The factored form is 5x2(x5)5x^2(x - 5). This example shows that the GCF of a polynomial can be a monomial containing both a numerical factor and a variable factor. When finding the GCF of expressions with variables, include each shared variable raised to the lowest power present across all terms — here, x2x^2 (the lower of x3x^3 and x2x^2).

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Updated 2026-04-21

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