Example

Factoring xy+3y+2x+6xy + 3y + 2x + 6

Factor xy+3y+2x+6xy + 3y + 2x + 6 using the grouping method. No single factor is common to all four terms, so apply factoring by grouping. Step 1 — Group terms with common factors: Pair the first two terms and the last two terms: (xy+3y)+(2x+6)(xy + 3y) + (2x + 6). Step 2 — Factor the GCF from each group: The GCF of xyxy and 3y3y is yy: y(x+3)y(x + 3). The GCF of 2x2x and 66 is 22: 2(x+3)2(x + 3). The expression becomes y(x+3)+2(x+3)y(x + 3) + 2(x + 3). Step 3 — Factor the common binomial: Both terms share the factor (x+3)(x + 3). Factor it out: (x+3)(y+2)(x + 3)(y + 2). Step 4 — Check by multiplying: (x+3)(y+2)=xy+2x+3y+6=xy+3y+2x+6(x + 3)(y + 2) = xy + 2x + 3y + 6 = xy + 3y + 2x + 6 ✓. The factored form is (x+3)(y+2)(x + 3)(y + 2).

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Updated 2026-05-13

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