Example

Factoring 6x212xc+6bx12bc6x^2 - 12xc + 6bx - 12bc

Factor 6x212xc+6bx12bc6x^2 - 12xc + 6bx - 12bc completely by extracting the greatest common factor and then factoring by grouping.

Step 1 — Check for a GCF: The four terms share a numerical factor of 66. Factor it out: 6(x22xc+bx2bc)6(x^2 - 2xc + bx - 2bc)

Step 2 — Classify the expression: The expression inside the parentheses has four terms, so apply factoring by grouping.

Step 3 — Group and factor each pair: Group the terms and factor the GCF from each pair: 6[x(x2c)+b(x2c)]6[x(x - 2c) + b(x - 2c)] Factor out the common binomial (x2c)(x - 2c): 6(x2c)(x+b)6(x - 2c)(x + b)

Step 4 — Check: Multiply to verify: 6(x2c)(x+b)=6(x2+bx2xc2bc)=6x212xc+6bx12bc6(x - 2c)(x + b) = 6(x^2 + bx - 2xc - 2bc) = 6x^2 - 12xc + 6bx - 12bc

The completely factored form is 6(x2c)(x+b)6(x - 2c)(x + b).

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Updated 2026-04-30

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