Example

Factoring xy+8y+3x+24xy + 8y + 3x + 24

Factor the polynomial xy+8y+3x+24xy + 8y + 3x + 24 by grouping. Because there is no single greatest common factor shared by all four terms, separate the polynomial into two pairs: (xy+8y)(xy + 8y) and (3x+24)(3x + 24). Next, factor the GCF from each pair individually. The GCF of the first pair is yy, yielding y(x+8)y(x + 8). The GCF of the second pair is 33, yielding 3(x+8)3(x + 8). The expression is now y(x+8)+3(x+8)y(x + 8) + 3(x + 8). Notice that both groups share the common binomial factor (x+8)(x + 8). Factor out this common binomial to obtain the final factored form: (x+8)(y+3)(x + 8)(y + 3). Check the result by multiplying: (x+8)(y+3)=xy+3x+8y+24(x + 8)(y + 3) = xy + 3x + 8y + 24, which is equivalent to the original polynomial.

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Updated 2026-04-29

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