Example

Factoring y2+4y7y28y^2 + 4y - 7y - 28

Factor the polynomial y2+4y7y28y^2 + 4y - 7y - 28 by grouping. With no overall GCF present, separate the four terms into two groups: (y2+4y)(y^2 + 4y) and (7y28)(-7y - 28). Factor the GCF from the first group, which is yy, yielding y(y+4)y(y + 4). Factor the GCF from the second group; taking out 7-7 ensures the signs inside the parentheses match the first group, yielding 7(y+4)-7(y + 4). The expression becomes y(y+4)7(y+4)y(y + 4) - 7(y + 4). Finally, factor out the common binomial (y+4)(y + 4) to arrive at the fully factored form: (y+4)(y7)(y + 4)(y - 7). Verify the factoring by multiplying the binomials.

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Updated 2026-04-29

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