Example

Factoring x2+3x−2x−6x^2 + 3x - 2x - 6

Factor x2+3x−2x−6x^2 + 3x - 2x - 6 using the grouping method. No single factor is common to all four terms, so apply factoring by grouping. Step 1 — Group terms with common factors: Pair the first two terms and the last two terms: (x2+3x)+(−2x−6)(x^2 + 3x) + (-2x - 6). Step 2 — Factor the GCF from each group: The GCF of x2x^2 and 3x3x is xx: x(x+3)x(x + 3). For the second group, the GCF of −2x-2x and −6-6 is −2-2 (use the negative GCF so that the binomial inside matches the first group): −2(x+3)-2(x + 3). The expression becomes x(x+3)−2(x+3)x(x + 3) - 2(x + 3). Step 3 — Factor the common binomial: Both terms share the factor (x+3)(x + 3). Factor it out: (x+3)(x−2)(x + 3)(x - 2). Step 4 — Check by multiplying to confirm the result equals the original expression. The factored form is (x+3)(x−2)(x + 3)(x - 2). When the second group begins with a negative term, be careful with signs when factoring its GCF — choosing the negative GCF (here −2-2 rather than 22) reverses the signs inside the parentheses and produces the matching binomial factor needed for step 3.

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Updated 2026-05-13

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