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Finding the Quotient 54a2b3÷(6ab5)54a^2b^3 \div (-6ab^5)

Divide two monomials that contain multiple variables and a negative denominator: 54a2b3÷(6ab5)54a^2b^3 \div (-6ab^5).

Step 1 — Rewrite as a fraction. 54a2b36ab5\frac{54a^2b^3}{-6ab^5}

Step 2 — Separate using fraction multiplication. Break the fraction into three parts — one for the coefficients and one for each variable: 546a2ab3b5\frac{54}{-6} \cdot \frac{a^2}{a} \cdot \frac{b^3}{b^5}

Step 3 — Simplify and use the Quotient Property. For the coefficients: 546=9\frac{54}{-6} = -9. For aa: a2a=a\frac{a^2}{a} = a. For bb: b3b5=1b2\frac{b^3}{b^5} = \frac{1}{b^2}. Combining these gives: 9a1b2-9 \cdot a \cdot \frac{1}{b^2}.

Step 4 — Multiply. 9ab2-\frac{9a}{b^2}

The quotient is 9ab2-\frac{9a}{b^2}.

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Updated 2026-04-29

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