1Cademy - Finding the Quotient $$\frac{7y^2 + 21}{7}$$

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Dividing Monomials

Example

Finding the Quotient $\frac{7y^2 + 21}{7}$

Divide a binomial by a constant: $\frac{7y^2 + 21}{7}$ .

Step 1 — Divide each term of the numerator by the denominator. Apply the reverse of the fraction addition property to split the fraction: $\frac{7y^2}{7} + \frac{21}{7}$ .

Step 2 — Simplify each fraction. For the first term: $\frac{7y^2}{7} = y^2$ (the coefficients divide to $1$ and the variable remains). For the second term: $\frac{21}{7} = 3$ .

The quotient is $y^2 + 3$ . This example illustrates the simplest case of dividing a polynomial by a monomial: when the divisor is a plain number (no variable), each term's coefficient is divided by that number while the variable parts stay unchanged.