Example

Identifying the Slope and y-Intercept of x+2y=6x + 2y = 6

When a linear equation is not already in slope-intercept form, the first step is to solve the equation for yy before the slope and y-intercept can be identified.

Given: x+2y=6x + 2y = 6

Step 1 — Solve for yy. Subtract xx from both sides:

2y=x+62y = -x + 6

Divide both sides by 22:

2y2=x+62\frac{2y}{2} = \frac{-x + 6}{2}

Split the fraction on the right using the rule a+bc=ac+bc\frac{a + b}{c} = \frac{a}{c} + \frac{b}{c}:

y=x2+62y = \frac{-x}{2} + \frac{6}{2}

Simplify:

y=12x+3y = -\frac{1}{2}x + 3

Step 2 — Compare to the slope-intercept form y=mx+by = mx + b.

Step 3 — Identify the slope: The coefficient of xx is 12-\frac{1}{2}, so m=12m = -\frac{1}{2}.

Step 4 — Identify the y-intercept: The constant term is 33, so the y-intercept is the point (0,3)(0, 3).

This example illustrates that when a linear equation is given in a form other than y=mx+by = mx + b, solving for yy first is essential before the slope and y-intercept can be read from the equation.

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Updated 2026-04-21

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