Example

Solving a Dual Stock Investment Application Using a System of Equations

Consider an investment of $7,0007{,}000 distributed across two stocks, one paying 11%11\% interest and the other paying 13%13\% interest. The total investment earns 12.5%12.5\% interest in one year. Let xx be the amount in the first stock and yy be the amount in the second stock. The system of equations is: x+y=7,000x + y = 7{,}000 0.11x+0.13y=0.125(7,000)0.11x + 0.13y = 0.125(7{,}000) The second equation simplifies to 0.11x+0.13y=8750.11x + 0.13y = 875. Solving this system yields x=1,750x = 1{,}750 and y=5,250y = 5{,}250. Therefore, $1,7501{,}750 is invested at 11%11\% and $5,2505{,}250 is invested at 13%13\%.

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Updated 2026-05-26

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