Example

Solving a Savings and Stock Interest Application Using a System of Equations

Apply the seven-step problem-solving strategy and a mixture table to solve an interest application involving two investments. Problem: Leon had $50,000\$50{,}000 to invest and hopes to earn 6.2%6.2\% interest per year. He will put some of the money into a stock fund that earns 7%7\% per year and the rest in to a savings account that earns 2%2\% per year. How much money should he put into each fund? 1. Read the problem. 2. Identify what to find: the amount to invest in each fund. 3. Name the unknowns. Let ss = the amount invested in stocks, and aa = the amount invested in the savings account. Organize into a table: / Fund / Principal ($) / Rate / Interest ($) / /---/---/---/---/ / Stocks / ss / 0.070.07 / 0.07s0.07s / / Savings / aa / 0.020.02 / 0.02a0.02a / / Total / 50,00050{,}000 / 0.0620.062 / 0.062(50,000)0.062(50{,}000) / 4. Translate into a system of equations: \left\{\begin{array}{l} s + a = 50{,}000 \ 0.07s + 0.02a = 0.062(50{,}000) \end{array} ight. 5. Solve the system by elimination. Multiply the top equation by 0.02-0.02: 0.02s0.02a=1,000-0.02s - 0.02a = -1{,}000 0.07s+0.02a=3,1000.07s + 0.02a = 3{,}100 Add the equations: 0.05s=2,1000.05s = 2{,}100 s=42,000s = 42{,}000 Substitute s=42,000s = 42{,}000 into the first equation: 42,000+a=50,00042{,}000 + a = 50{,}000 a=8,000a = 8{,}000 6. Check the answer. 42,000+8,000=50,00042{,}000 + 8{,}000 = 50{,}000 \checkmark 0.07(42,000)+0.02(8,000)=2,940+160=3,1000.07(42{,}000) + 0.02(8{,}000) = 2{,}940 + 160 = 3{,}100 0.062(50,000)=3,1000.062(50{,}000) = 3{,}100 \checkmark 7. Answer the question. Leon should invest $42,000\$42{,}000 in the stock fund and $8,000\$8{,}000 in the savings account.

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Updated 2026-05-25

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