Example

Solving a Sulfuric Acid Mixture Application Using a System of Equations

A system of equations can be used to solve sulfuric acid mixture applications. For example, if 150150 milliliters of a 30%30\% sulfuric acid solution is needed, but only 25%25\% and 50%50\% solutions are available, we can determine the required amounts of each. Let xx be the volume of the 25%25\% solution and yy be the volume of the 50%50\% solution. The system of equations is set up as follows: x+y=150x + y = 150 0.25x+0.5y=0.30(150)0.25x + 0.5y = 0.30(150) Solving this system provides the specific volumes of each starting solution needed to achieve the target mixture.

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Updated 2026-05-25

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