Example

Solving a Hydrochloric Acid Mixture Problem Using a System of Equations

A system of equations can be used to solve hydrochloric acid mixture applications. For instance, if 250250 milliliters of a 25%25\% hydrochloric acid solution is required, and only 10%10\% and 40%40\% solutions are available, the necessary volumes of each can be found. Let xx be the volume of the 10%10\% solution and yy be the volume of the 40%40\% solution. The system of equations translates to: x+y=250x + y = 250 0.10x+0.40y=0.25(250)0.10x + 0.40y = 0.25(250) Solving this system yields the exact amounts of the 10%10\% and 40%40\% solutions that must be mixed.

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Updated 2026-05-25

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