Example

Solving for Two Consecutive Odd Integers Whose Product is 323323

Apply the problem-solving strategy to find two consecutive odd integers whose product is 323323.

  1. Identify and Name: Let nn represent the first odd integer. The next consecutive odd integer is n+2n + 2.
  2. Translate: The product of the two consecutive odd integers is 323323, which translates to the equation n(n+2)=323n(n + 2) = 323.
  3. Solve: Distribute nn to get n2+2n=323n^2 + 2n = 323. Bring all terms to one side to write the quadratic equation in standard form: n2+2n323=0n^2 + 2n - 323 = 0. Factor the trinomial to obtain (n17)(n+19)=0(n - 17)(n + 19) = 0. Using the Zero Product Property, solve to find n=17n = 17 or n=19n = -19.

There are two sets of solutions:

  • If the first integer is 1717, the next consecutive odd integer is 17+2=1917 + 2 = 19.
  • If the first integer is 19-19, the next consecutive odd integer is 19+2=17-19 + 2 = -17.
  1. Check: 1719=32317 \cdot 19 = 323 and 19(17)=323-19(-17) = 323. Both pairs are valid solutions.
  2. Answer: The consecutive odd integers are 1717 and 1919, and 19-19 and 17-17.

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Updated 2026-04-30

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