Example

Solving for Two Consecutive Odd Integers Whose Product is 255255

Apply the problem-solving strategy to find two consecutive odd integers whose product is 255255.

Let nn be the first odd integer, making the next consecutive odd integer n+2n + 2. The product of the two integers is 255255, leading to the algebraic equation: n(n+2)=255n(n + 2) = 255. Expanding the left side yields n2+2n=255n^2 + 2n = 255. Subtract 255255 from both sides to convert the quadratic equation into standard form: n2+2n255=0n^2 + 2n - 255 = 0. Factor the trinomial to get (n15)(n+17)=0(n - 15)(n + 17) = 0. Setting each factor to zero using the Zero Product Property gives the solutions n=15n = 15 and n=17n = -17.

This results in two possible pairs of consecutive odd integers:

  • For n=15n = 15, the next odd integer is 15+2=1715 + 2 = 17.
  • For n=17n = -17, the next odd integer is 17+2=15-17 + 2 = -15.

The valid sets of consecutive odd integers are 1515 and 1717, and 17-17 and 15-15.

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Updated 2026-04-30

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