Example

Solving 12(y5)=14(y1)\frac{1}{2}(y - 5) = \frac{1}{4}(y - 1) by Clearing Fractions

To solve the linear equation 12(y5)=14(y1)\frac{1}{2}(y - 5) = \frac{1}{4}(y - 1), one efficient approach is to clear the fractions before distributing. First, identify the least common denominator (LCD) of the fractions 12\frac{1}{2} and 14\frac{1}{4}, which is 44. Multiply both sides of the equation by 44: 412(y5)=414(y1)4 \cdot \frac{1}{2}(y - 5) = 4 \cdot \frac{1}{4}(y - 1). Simplifying the fractional parts yields 2(y5)=1(y1)2(y - 5) = 1(y - 1). Next, distribute the constants into the parentheses to get 2y10=y12y - 10 = y - 1. Collect the variable terms on the left side by subtracting yy from both sides, resulting in y10=1y - 10 = -1. Finally, collect the constant terms on the right side by adding 1010 to both sides, which gives the solution y=9y = 9. Alternatively, one could distribute the fractions first and then multiply every term by the LCD, but clearing fractions without distributing first is often simpler and less error-prone.

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Updated 2026-05-02

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Ch.2 Solving Linear Equations - Intermediate Algebra @ OpenStax

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