Example

Solving 5=12y+23y34y5 = \frac{1}{2}y + \frac{2}{3}y - \frac{3}{4}y by Clearing Fractions

To solve the linear equation 5=12y+23y34y5 = \frac{1}{2}y + \frac{2}{3}y - \frac{3}{4}y, use the strategy of clearing fractions first.

Step 1: Find the least common denominator (LCD) of all the fractions in the equation. The denominators are 22, 33, and 44. The LCD is 1212.

Step 2: Multiply both sides of the equation by 1212 to clear the fractions: 12(5)=12(12y+23y34y)12(5) = 12\left(\frac{1}{2}y + \frac{2}{3}y - \frac{3}{4}y\right)

Distribute the 1212 to every term on the right side: 12(5)=12(12y)+12(23y)12(34y)12(5) = 12\left(\frac{1}{2}y\right) + 12\left(\frac{2}{3}y\right) - 12\left(\frac{3}{4}y\right)

Simplify each product. Notice there are no more fractions: 60=6y+8y9y60 = 6y + 8y - 9y

Step 3: Solve the resulting equation. Combine like terms on the right side: 60=5y60 = 5y

Divide both sides by 55 to isolate yy: 605=5y5\frac{60}{5} = \frac{5y}{5} 12=y12 = y

Check the solution by substituting y=12y = 12 into the original equation: 5=?12(12)+23(12)34(12)5 \stackrel{?}{=} \frac{1}{2}(12) + \frac{2}{3}(12) - \frac{3}{4}(12) 5=?6+895 \stackrel{?}{=} 6 + 8 - 9 5=55 = 5 \checkmark Because both sides are equal, y=12y = 12 is verified as the correct solution.

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Updated 2026-05-02

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Ch.2 Solving Linear Equations - Intermediate Algebra @ OpenStax

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