Example

Solving rac{2s+3}{2} + 1 = rac{3s+2}{4} by Clearing Fractions

To solve the linear equation rac{2s+3}{2} + 1 = rac{3s+2}{4} by clearing fractions, first find the LCD for the denominators 22 and 44, which is 44. Multiply every term on both sides by 44, ensuring the integer term 11 is also multiplied by the LCD:

ight) + 4(1) = 4\left( rac{3s+2}{4} ight)$$ Simplify the terms to remove the fractions: $$2(2s+3) + 4 = 3s+2$$ Distribute the $$2$$ on the left side: $$4s+6+4=3s+2$$ Combine the constant terms on the left: $$4s+10=3s+2$$ Collect the variable terms to the left by subtracting $$3s$$ from both sides: $$s+10=2$$ Subtract $$10$$ from both sides to isolate the variable: $$s=-8$$ Checking the solution by substituting $$-8$$ in the original equation confirms the solution.

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Updated 2026-04-22

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